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Thread tagged as: Problem, Addons

How to do page conditionals in a header (global layout)

I've looked through the conditionals docs but my code doesn't seem to be working. I am trying to add a conditional statement to my global header so that I can display something if it is the homepage else, do something different.

Below is what I tried but I don't think it is correct as it is a global value, not inside a smaller template. I can't find the correct answer in the docs or the new forum.

<perch:if id="pageID" match="eq" value="1">
####
<perch:else>
###
</perch:if>
Andrew Cetnarskyj

Andrew Cetnarskyj 0 points

  • 7 years ago
Drew McLellan

Drew McLellan 2638 points
Perch Support

7 years ago

Where's pageID coming from? Is it a layout attribute?
Andrew Cetnarskyj

Andrew Cetnarskyj 0 points

7 years ago

No I wasn't passing it in as a layout variable, I thought it would be globally available from the queries that are run for the page content?
Drew McLellan

Drew McLellan 2638 points
Perch Support

7 years ago

It's not globally available.

Why not use a layout variable to indicate the home page?
Robert Ketter

Robert Ketter 103 points

7 years ago

Andrew, I hope this helps. Along the lines of what Drew is suggesting.

example.php

<?php

perch_layout('global.header', array(
    'homepage' => true
));

?>

global.header.php

<?php if(perch_layout_var('homepage',true)) { // if it's the homepage output this?>

  <h1>Yep, it's the Homepage</h1>

<?php }else{ // otherwise output this?>

  <h1>Sorry, This isn't the Homepage!</h1>

<?php } ?>

Robert